(12x+20)^2+(48-5x)^2=4225

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Solution for (12x+20)^2+(48-5x)^2=4225 equation: 



(12x+20)^2+(48-5x)^2=4225

We move all terms to the left:

(12x+20)^2+(48-5x)^2-(4225)=0

We add all the numbers together, and all the variables

(12x+20)^2+(-5x+48)^2-4225=0

We move all terms containing x to the left, all other terms to the right

(12x+20)^2+(-5x+48)^2=4225

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